How do you solve $x^{2} + 5 x + 4 \leq 0$ $x^2+5x+4<=0$ ?

Question

How do you solve $x^{2} + 5 x + 4 \leq 0$ $x^2+5x+4<=0$ ?

1 Answer

Related questions

What are common mistakes students make when solving polynomial inequalities?
How do I solve a polynomial inequality?
How do I solve the polynomial inequality $- 2 (m - 3) < 5 (m + 1) - 12$ $-2(m-3)<5(m+1)-12$ ?
How do I solve the polynomial inequality $- 6 \leq 2 (x - 5) < 7$ $-6<=2(x-5)<7$ ?
How do I solve the polynomial inequality $1 < 2 x + 3 < 11$ $1<2x+3<11$ ?
How do I solve the polynomial inequality $- 12 < - 2 (x + 1) \leq 18$ $-12<-2(x+1)<=18$ ?
How do you solve the inequality $6 x^{2} - 5 x > 6$ $6x^2-5x>6$ ?
How do you solve $x^{2} - 4 x - 21 \leq 0$ $x^2 - 4x - 21<=0$ A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)?
How do you solve quadratic inequality, graph, and write in interval notation $x^{2} - 8 x + 15 > 0$ $x^2 - 8x + 15 >0$ ?
How do you solve $- x^{2} - x + 6 < 0$ $-x^2 - x + 6 < 0$ ?

Impact of this question

1669 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-26T19:53:49

$x \in [- 4, - 1]$ $x in [-4, -1]$

Explanation:

$x^{2} + 5 x + 4 = (x + 4) (x + 1)$ $x^2+5x+4 = (x+4)(x+1)$

This is zero when $x = - 4$ $x=-4$ or $x = - 1$ $x=-1$

The quadratic has a positive leading coefficient, so is is an upright parabola, crossing the $x$ $x$ axis at $(- 4, 0)$ $(-4, 0)$ and $(- 1, 0)$ $(-1, 0)$ .

Hence any $x \in [- 4, - 1]$ $x in [-4, -1]$ satisfies the required inequality and any value of $x$ $x$ outside that closed interval does not.

graph{x^2+5x+4 [-10, 10, -5, 5]}

Science

Math

Humanities

... and beyond

How do you solve $x^{2} + 5 x + 4 \leq 0$ $x^2+5x+4<=0$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve x2+5x+4≤0x^2+5x+4<=0?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $x^{2} + 5 x + 4 \leq 0$ $x^2+5x+4<=0$ ?