How do you solve #x^2-4x>=5#? Precalculus Solving Rational Inequalities Polynomial Inequalities 1 Answer Sahar Mulla ❤ Feb 1, 2018 #x^2−4x≥5# #x^2−4x-5≥0# #x^2+x-5x-5≥0# #x(x+1)-5(x+1)≥0# #(x-5)(x+1)≥0# #:.(x-5)≥0# and #(x+1)≥0# #x>=5# and #x>=-1# #x<=5# as it will also be greater than -1 then. -Sahar. Answer link Related questions What are common mistakes students make when solving polynomial inequalities? How do I solve a polynomial inequality? How do I solve the polynomial inequality #-2(m-3)<5(m+1)-12#? How do I solve the polynomial inequality #-6<=2(x-5)<7#? How do I solve the polynomial inequality #1<2x+3<11#? How do I solve the polynomial inequality #-12<-2(x+1)<=18#? How do you solve the inequality #6x^2-5x>6#? How do you solve #x^2 - 4x - 21<=0# A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)? How do you solve quadratic inequality, graph, and write in interval notation #x^2 - 8x + 15 >0#? How do you solve #-x^2 - x + 6 < 0#? See all questions in Polynomial Inequalities Impact of this question 1250 views around the world You can reuse this answer Creative Commons License