How do you solve #x^(2/3)+10=19#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Noah G Sep 24, 2016 #x^(2/3) = 9# #(x^(2/3))^3 = 9^3# #x^2 = 729# #x = +-27# Hopefully this helps! Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1014 views around the world You can reuse this answer Creative Commons License