How do you solve #x^2+2x-120=0# by completing the square?
1 Answer
Oct 11, 2016
Explanation:
The difference of squares identity can be written:
#a^2-b^2 = (a-b)(a+b)#
Use this with
#0 = x^2+2x-120#
#color(white)(0) = x^2+2x+1-121#
#color(white)(0) = (x+1)^2-11^2#
#color(white)(0) = ((x+1)-11)((x+1)+11)#
#color(white)(0) = (x-10)(x+12)#
Hence roots