How do you solve $x^{2} - 14 x + 49 \geq 0$ $x^2-14x+49>=0$ ?

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Answer 1 · 2017-01-26T10:51:23

The answer is $x in RR$

Let's factorise the inequality

$x^2-14x+49=(x-7)(x-7)=(x-7)^2>=0$

Let $f(x)=(x-7)^2$

The domain of $f(x)$ is $D_f(x)=RR$

$AA x in RR, f(x)>=0$

How do you solve x^2-14x+49>=0x2−14x+49≥0x^2-14x+49>=0?