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How do you solve #x^2 - 121#?

1 Answer

Apr 1, 2018

#x=11, x=-11#

Explanation:

Using the difference of squares, which states that

#(x^2-a^2)=(x+a)(x-a)#:

#(x^2-121)=0#

#(x+11)(x-11)=0#

#x=11, x=-11#

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