How do you solve using gaussian elimination or gauss-jordan elimination, #x-3y=6# and #x+6y=0#? Precalculus Matrix Row Operations Gaussian Elimination 1 Answer Cem Sentin Mar 12, 2018 #x=4# and #y=-2/3# Explanation: From #x+6y=0#, #x=-6y#. Hence #x-3y=6# became #-9y=6#. So, #y=6/(-9)=-2/3# and #x=(-6)*(-2/3)=4# Answer link Related questions How do I use Gaussian elimination to solve a system of equations? How do I find the determinant of a matrix using Gaussian elimination? How do I find the inverse of a matrix? How do I find the rank of a matrix using Gaussian elimination? What is naive Gaussian elimination? What is Gauss-Jordan elimination? How do you solve the system #w+4x+3y-11z=42# , #6w+9x+8y-9z=31# and #-5w+6x+3y+13z=2#, #8w+3x-7y+6z=31#? How do you solve the system #-5 = -64a + 16b - 4c + d#, #-4 = -27a + 9b - 3c + d#, #-3 = -8a +... How do you solve the system #17x - y + 2z = -9#, #x + y - 4z = 8#, #3x - 2y - 12z = 24#? How do you solve the system #x= 175+15y#, #.196x= 10.4y#, #z=10*y#? See all questions in Gaussian Elimination Impact of this question 1306 views around the world You can reuse this answer Creative Commons License