How do you solve titration problems?

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How do you solve titration problems?

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Answer 1 · 2017-02-06T09:21:08

Try using dimensions when you do the calculations.

Explanation:

With a titration a measured quantity of titrant is added to a known mass of known molar quantity.

We use the relationship, $moles = \frac{Mass}{molar mass}$ $"moles "="Mass"/"molar mass"$ ,

and $Molarity (concentration)$ $"Molarity (concentration)"$ $=$ $=$ $\frac{Moles of stuff}{Volume of solution}$ $"Moles of stuff"/"Volume of solution"$

Now when we use $molarity$ $"molarity"$ we can preserve the dimensions: $m o l \cdot L^{- 1}$ $mol*L^-1$ are the units for concentration.

When we multiply a concentration by a VOLUME, we get the product, $mol*cancel(L^-1)xxcancelL=mol$ .

Now a chemical reaction is VITAL when you do a titration. For acid/base titrations this is typically:

$H_3O^+ + HO^(-) rarr2H_2O(l)$

The stoichiometric equivalence must be borne in mind, when you do the calculation. So, as a general rule, you must have the appropriate, stoichiometrically balanced chemical equation. Most of the time, there is 1:1 molar equivalence, and,

$C_1V_1=C_2V_2$ , where $C-="concentration"$ as we defined.

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How do you solve titration problems?

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