How do you solve titration problems?

1 Answer
anor277
Feb 6, 2017

Try using dimensions when you do the calculations.

Explanation:

With a titration a measured quantity of titrant is added to a known mass of known molar quantity.

We use the relationship, "moles "="Mass"/"molar mass",

and "Molarity (concentration)" = "Moles of stuff"/"Volume of solution"

Now when we use "molarity" we can preserve the dimensions: mol*L^-1 are the units for concentration.

When we multiply a concentration by a VOLUME, we get the product, mol*cancel(L^-1)xxcancelL=mol.

Now a chemical reaction is VITAL when you do a titration. For acid/base titrations this is typically:

H_3O^+ + HO^(-) rarr2H_2O(l)

The stoichiometric equivalence must be borne in mind, when you do the calculation. So, as a general rule, you must have the appropriate, stoichiometrically balanced chemical equation. Most of the time, there is 1:1 molar equivalence, and,

C_1V_1=C_2V_2, where C-="concentration" as we defined.

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