How do you solve the triangle of $A=76^circ, a=18, b=20$ ?

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Answer 1 · 2017-01-11T03:25:39

There is no solution

We attempt to use the law of sines to solve the triangle.
The law states:
$a/sin(A) = b/sin(B) = c/sin(C)$

$18/sin(76) = 20/sin(B)$

$20*sin(76) = 18*sin(B)$

$20/18 * sin(76) = sin(B)$

$arcsin(20/18 * sin(76)) = B$

$B = arcsin(1.078)$

$B =$ error

Therefore, there is no solution.

How do you solve the triangle of A=76^circ, a=18, b=20A=76^circ, a=18, b=20?