How do you solve the triangle if A= 50 degrees, B=65, a=10?

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Answer 1 · 2015-10-02T17:52:53

Refer to explanation

In a triangle the sum of all angles equals to 180 degrees.Hence let C be the third angle we have that

$A+B+C=180=>C=180-A-B=>C=180-50-65=65^o$

Now that we know all angles we use the law of sines which states that in a triangle we have that

$sinA/a=sinB/b=sinC/c$

For side b we have that

$sinA/a=sinB/b=>b=sinB/sinA*a=>b=sin65/sin50*10=11.83$

Because $B=C=65^o$ this makes the triangle isosceles hence
$b=c=11.83$