How do you solve the triangle given $B=15^circ30', a=4.5, b=6.8$ ?

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Answer 1 · 2018-03-28T10:04:26

$color(blue)("Area of Triangle " A_t = 6.63" sq units"$

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$hat B = 15.5^@, a = 4.5, b = 6.8$

$sin A = (sin B * a) / b = (sin (15.5) * 4.5) / 6.8 = 0.1768$

$hat A = sin ^_1 0.1768 = 10.18^@$

$hat C = 180 - hat A - hat B = 180 - 10.18 - 15.5 = 154.32^@$

$"Area of Triangle " A_t = (1/2) a b sin C = (1/2) * 4.5 * 6.8 * sin 154.32 = 6.63" sq units"$

How do you solve the triangle given B=15^circ30', a=4.5, b=6.8B=15^circ30', a=4.5, b=6.8?