How do you solve the triangle given a=8, b=24, c=18?

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Answer 1 · 2018-02-24T16:56:18

Three angles are $color(blue)(hat A = 14.63^@, hat B = 130.75^@, hat C = 34.62^@$

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Known three sides. To find the three angles.

$A_t = sqrt (s (s-a) (s-b) (s - c))$ where s is the semi perimeter of the triangle.

$s = (8 + 24 + 18)/2 = 25$

$A_t = sqrt(25 * (25-8) (25-24) (25-18))= 54.54$

But $A_t = (1/2) b c sin A$

$:. sin A = (2 * A_t) / (b c) = (2 * 54.54) / (24 * 18) = 0.2525$

$hat A = sin ^-1 0.2525 = 14.63^@$

Similarly,
$hat B = sin ^-1 ((2 * 54.54) / (8*18) )= (180 - 49.24) = 130.75^@$ since it is an obtuse angle.

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$hat C = sin ^-1 ((2 * 54.54) / (8*24)) = 34.62$