How do you solve the triangle given A=36, a=10, b=19?

1 Answer
Mr. Mike
Mar 29, 2018

There is no triangle possible with these measures.

Explanation:

We start with the law of sines.

sin(36^@)/10=sin(B)/19

sin(B) = 19/10*sin(36^@)=1.9*sqrt((5-sqrt(5))/8)~~1.1168

But we know that this is impossible because sin(B) must be less than or equal to 1, so we cannot construct a triangle with these measures.

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