How do you solve the system #y= 2x + 5# and #y= 3x - 8# by substitution? Algebra Linear Inequalities and Absolute Value Linear Inequalities in Two Variables 1 Answer MeneerNask May 28, 2015 You substitute the #y#-value of one equation as expressed in #x# into the other. In this case we get: #2x+5=3x-8#, subtract #2x# from both sides #->5=x-8#, add #8# to both sides #->13=x->x=13# Answer link Related questions How do you graph linear inequalities in two variables? How many solutions does a linear inequality in two variables have? How do you know if you need to shade above or below the line? What is the difference between graphing #x=1# on a coordinate plane and on a number line? How do you graph #y \le 4x+3#? How do you graph #3x-4y \ge 12#? How do you graph #y+5 \le -4x+10#? How do you graph the linear inequality #-2x - 5y<10#? How do you graph the inequality #–3x – 4y<=12#? How do you graph the region #3x-4y>= -12#? See all questions in Linear Inequalities in Two Variables Impact of this question 1707 views around the world You can reuse this answer Creative Commons License