How do you solve the system #x-6y+4z=-12#, #x+y-4z=12#, and #2x+2y+5z=-15#?
1 Answer
Please see the explanation for steps leading to the answer:
Explanation:
Write the 3 equations as an augmented matrix:
Subtract row 1 from row 2:
Multiply row 1 by -2 and add to row 3:
Multiply row 2 by -2 and add to row 3:
Divide row 3 by 13:
Multiply row 3 by 8 and add to row 2:
Multiply row 3 by -4 and add to row 1:
Divide row 2 by 7:
Multiply row 2 by 6 and add to row 1: