How do you solve the system #x+2y=5# and #5x-y=3#?

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How do you solve the system #x+2y=5# and #5x-y=3#?

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Answer 1 · 2015-06-04T21:47:41

From the first equation we learn that
#x=5-2y#

If we substitute that value for #x# in the second equation:
#5*(5-2y)-y=3->#
#25-10y-y=3-># subtract 3
#22-11y=0->22=11y->y=2#
Back to the first equation:
#x=5-2*2=1#

Check the answer:
#1+2*2=5and5*1-2=3#

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How do you solve the system #x+2y=5# and #5x-y=3#?

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