Perform the Gauss Jordan elimination on the augmented matrix
#A=((1,2,-4,|,13),(3,4,-2,|,19),(3,0,2,|,3))#
I have written the equations not in the sequence as in the question in order to get #1# as pivot.
Perform the folowing operations on the rows of the matrix
#R2larrR2-3R1# ; #R3larrR3-3R1#
#A=((1,2,-4,|,13),(0,-2,10,|,-20),(0,-6,14,|,-36))#
#R3larrR3-3R2#
#A=((1,2,-4,|,13),(0,-2,10,|,-20),(0,0,-16,|,24))#
#R3larr(R3)/(-16)#
#A=((1,2,-4,|,13),(0,-2,10,|,-20),(0,0,1,|,-3/2))#
#R1larrR1+4R3# ; #R2larrR2-10R3#
#A=((1,2,0,|,7),(0,-2,0,|,-5),(0,0,1,|,-3/2))#
#R1larrR1+R2#
#A=((1,0,0,|,2),(0,-2,0,|,-5),(0,0,1,|,-3/2))#
#R2larr(R2)/(-2)#
#A=((1,0,0,|,2),(0,1,0,|,5/2),(0,0,1,|,-3/2))#
Thus, solution of equation system is #x=2#, #y=5/2# and #z=-3/2#