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How do you solve the system #3x+2y=19# and #2x-3y=-9# by substitution?

1 Answer

May 24, 2015

#3x + 2y = 19 -> 3x = 19 - 2y -> x = (19 - 2y)/3#

#2x - 3y = -9 -> (2/3).(19 - 2y) - 3y = -9#

#38 - 4y - 9y = -27 -> -13y = -27 - 38 = - 65#

#y = 65/13# = 5

#x = (19 - 10)/3 = 9/3 = 3#

Check: 3(3) + 2(5) = 19. OK

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