How do you solve the system #2x = 3 - y# and #2y = 12 - x# by substitution?

1 Answer
May 25, 2015

#2x = 3 - y#
# y = 3 - 2x#............equation #(1)#

#2y = 12 - x# ........equation #(2)#

substituting equation #(1)# in equation #(2)#
#2(3-2x) = 12 - x#
#6 - 4x = 12 - x#
# -6 = 3x#
# x =-2#

finding #y# :
# y = 3 - 2x# , from equation #(1)#
# = 3 - 2(-2)#
#= 3+4 = 7#

solutions for the system of equations are
#color (blue)(x=-2 and y = 7#