How do you solve the simultaneous equations #4x + 3y = 11# and #4x - 2y = 6#?

2 Answers
Adrian D.
Jul 20, 2015

#x=2,y=1#

Explanation:

Subtract the second equation from the first and solve for #y#:
#(4x+3y)-(4x-2y)=11-6# => #5y=5# => #y=1#

Use this value in the first equation and solve for #x#:
#4x+3y=4x+3=11# => #4x=8# => #x=2#

Gió
Jul 20, 2015

I found:
#x=2#
#y=1#

Explanation:

You can multiply the first equation by #-1# and then add the two equations (in columns) as:
#{-4x-3y=-11#
#{4x-2y=6# add them:
#0-5y=-5#
#y=1#
Substitute back into the first equation:
#4x+3=11#
#4x=8#
#x=2#

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