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How do you solve the right triangle given the hypotenuse is 12 and it is a 30-60-90 triangle?

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May 23, 2015

A = 30, B = 60 and C = 90

#sin A = sin 30 = 1/2 = a/c = a/12 -> a = 12/2 = 6#

#cos A = cos 60 = (sqrt3)/2 = b/12 --> b = 6sqrt3 = 10.39#

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