How do you solve the quadratic $y^2+2y+1=0$ using any method?

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Answer 1 · 2016-08-11T16:21:06

$y=-1$

$y^2+2y+1=0$

$"Solution -1"$

$y^2+2y+1=(y+1)^2$

$(y+1)^2=0$

$y=-1$

$"Solution-2"$

$Delta=sqrt(4-4*1*1)=0$

$y_("1,2")=(-b±Delta)/(2*a)$

$"So "Delta =0 " There is one root"$

$y=(-2±0)/(2*1)$

$y=-1$

How do you solve the quadratic y^2+2y+1=0y^2+2y+1=0 using any method?