How do you solve the quadratic x-4/x=21/53 using any method?

1 Answer
Nallasivam V
Jan 3, 2017

x=(21+sqrt45385)/106

x=(21-sqrt45385)/106

Explanation:

Given -

x-4/x=21/53

x^2-4=21/53x
x^2-21/53x=4
x^2-21/53x+441/11236=4+441/11236
(x-21/106)^2=(44944+441)/11236=45385/11236
x-21/106=+-sqrt(45385/11236)
x-21/106=+-sqrt(45385)/(sqrt(11236)
x-21/106=+-sqrt(45385)/106

x=21/106+sqrt(45385)/106
x=(21+sqrt45385)/106

x=21/106-sqrt(45385)/106
x=(21-sqrt45385)/106

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