How do you solve the quadratic #x^2+x=-1# using any method?
1 Answer
Aug 14, 2016
Use the quadratic formula to find roots:
#-1/2+-sqrt(3)/2i#
Explanation:
If you add
#x^2+x+1=0#
This is in the form
This has roots given by the quadratic formula:
#x = (-b+-sqrt(b^2-4ac))/(2a)#
#=(-1+-sqrt(1^2-4(1)(1)))/(2*1)#
#=(-1+-sqrt(-3))/2#
#=-1/2+-sqrt(3)/2i#
