How do you solve the quadratic $7 r^{2} + 8 = 281$ $7r^2+8=281$ using any method?

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How do you solve the quadratic $7 r^{2} + 8 = 281$ $7r^2+8=281$ using any method?

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Answer 1 · 2016-08-16T06:12:13

$r = \pm \sqrt{39}$ $r=+-sqrt(39)$

Explanation:

Given -

$7 r^{2} + 8 = 281$ $7r^2+8=281$
$7 r^{2} = 281 - 8 = 273$ $7r^2=281-8=273$
$r^{2} = \frac{273}{7} = 39$ $r^2=273/7=39$

$r = \pm \sqrt{39}$ $r=+-sqrt(39)$

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How do you solve the quadratic $7 r^{2} + 8 = 281$ $7r^2+8=281$ using any method?

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How do you solve the quadratic $7 r^{2} + 8 = 281$ $7r^2+8=281$ using any method?