How do you solve the quadratic $6 x^{2} + 9 x - 6 = 0$ $6x^2+9x-6=0$ using any method?

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Answer 1 · 2016-10-12T07:37:50

$x = {- 2, \frac{1}{2}}$ $x={-2,1/2}$

$6 x^{2} + 9 x - 6 = 0$ $6x^2+9x-6=0$

$solution 1:$ $"solution 1:"$

$factor the equation :$ $"factor the equation :"$
$3 (x + 2) (2 x - 1) = 0$ $3(x+2)(2x-1)=0$

$if x + 2 = 0; x = - 2$ $"if " x+2=0" ; "x=-2$

$if 2 x - 1 = 0; 2 x = 1; x = \frac{1}{2}$ $"if "2x-1=0" ; "2x=1" ; "x=1/2$

$solution 2:$ $"solution 2:"$

$use quadratic formula$ $"use quadratic formula"$

$a x^{2} + b x + c = 0$ $ax^2+bx+c=0$

$6 x^{2} + 9 x - 6 = 0$ $6x^2+9x-6=0$

$a = 6; b = 9; c = - 6$ $a=6" ; "b=9" ; "c=-6$

$Delta=sqrt(b^2-4*a*c)$

$Delta=sqrt(9^2+4*6*6)$

$Delta=sqrt(81+144)$

$Delta=sqrt(225)$

$x_1=(-9-sqrt(225))/(2*6)=(-9-15)/12=-24/12=-2$

$x_2=(-9+sqrt 225)/(2*6)=(-9+15)/12=6/12=1/2$

How do you solve the quadratic 6x^2+9x-6=06x2+9x−6=06x^2+9x-6=0 using any method?