How do you solve the quadratic 3r25=10 using any method?

1 Answer
Dec 2, 2016

r=±153i

Explanation:

3r25=10
a2a+5aa2a+5aaaAdd 5 to both sides

3r2=5

3r23=53aaaDivide both sides by 3

r2=53

r2=53aaaSquare root both sides

r=±i53aaThe negative inside the square root comes out as i.

r=±i5333aaaRationalize the denominator

r=±i153=±153i