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How do you solve the inequality $x^{2} + 4 \leq 4 x$ $x^2+4<=4x$ and write your answer in interval notation?

1 Answer

Feb 13, 2017

There is only one solution $S = {2}$ $S={2}$

Explanation:

Let's rewrite and factorise the inequality

$x^{2} + 4 \leq 4 x$ $x^2+4<=4x$

$x^{2} - 4 x + 4 \leq 0$ $x^2-4x+4<=0$

${(x - 2)}^{2} \leq 0$ $(x-2)^2<=0$

There is only one solution,

$x = 2$ $x=2$

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