How do you solve the inequality $x^2+1<0$ and write your answer in interval notation?

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Answer 1 · 2017-09-12T17:46:57

$"no solution"$

$x^2+1" is entirely above the x-axis and so"$
graph{x^2+1 [-12.66, 12.65, -6.33, 6.33]}

$rArrx^2+1<0" has no real solutions"$

How do you solve the inequality x^2+1<0x^2+1<0 and write your answer in interval notation?