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How do you solve the inequality $x^{2} + 1 < 0$ $x^2+1<0$ and write your answer in interval notation?

1 Answer

Sep 12, 2017

$no solution$ $"no solution"$

Explanation:

$x^{2} + 1 is entirely above the x-axis and so$ $x^2+1" is entirely above the x-axis and so"$
graph{x^2+1 [-12.66, 12.65, -6.33, 6.33]}

$\Rightarrow x^{2} + 1 < 0 has no real solutions$ $rArrx^2+1<0" has no real solutions"$

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