How do you solve the inequality #3a ≤ - 2 - 3a# or # 3a > 2 - a#?

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Answer 1 · 2018-04-11T13:01:43

Please look below.

The first inequality can be solved by adding #3a# then dividing by #6# :

#3a <= -2-3a#

#6a <= -2#

#a <= - 1/3#

The second inequality can be solved by adding #a# then dividing
by #4# :

#3a >2-a#

#4a > 2#

#a > 1/2#

From these two inequalities we get:

#a<=-1/3# , #1/2 < a#