How do you solve the following system of equations?: $x-2y=13 , 4x+3y=8$ ?

Question

3692 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-03T08:18:06

The solution for the system of equations is
$color(blue)(x=5,y=-4$

$x-2y=13$

$x=color(blue)(13+2y$ .....equation $1$

$4x+3y=8$ .....equation $2$

Solving by substitution :

Substituting equation $1$ in equation $2$ to find $y$

$4x+3y=8$

$4*(color(blue)(13+2y))+3y=8$

$4*(color(blue)(13) ) + 4 *color(blue)((2y))+3y=8$

$52+8y+3y=8$

$52+11y=8$

$11y=8-52$

$11y=-44$

$y=(-44)/11$

$color(blue)(y=-4$

Now, we substitute this value of $y$ in equation $1$ to find $x$
$x=13+2y$

$x=13+2*color(blue)((-4)$

$x=13-8$

$color(blue)(x=5$

How do you solve the following system of equations?: x-2y=13 , 4x+3y=8x-2y=13 , 4x+3y=8?