How do you solve the following system of equations?: #x-2y=13 , 4x+3y=8#?

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Answer 1 · 2015-12-03T08:18:06

The solution for the system of equations is
#color(blue)(x=5,y=-4#

#x-2y=13#

#x=color(blue)(13+2y#.....equation #1#

#4x+3y=8#.....equation #2#

Solving by substitution :

Substituting equation #1# in equation #2# to find #y#

#4x+3y=8#

#4*(color(blue)(13+2y))+3y=8#

#4*(color(blue)(13) ) + 4 *color(blue)((2y))+3y=8#

#52+8y+3y=8#

#52+11y=8#

#11y=8-52#

#11y=-44#

#y=(-44)/11#

#color(blue)(y=-4#

Now, we substitute this value of #y# in equation #1# to find #x#
#x=13+2y#

#x=13+2*color(blue)((-4)#

#x=13-8#

#color(blue)(x=5#