How do you solve the following linear system: #4x-y=-4 , 3x+3y=-18 #? Algebra Systems of Equations and Inequalities Linear Systems with Addition or Subtraction 1 Answer Cem Sentin Jun 21, 2018 #x=-2# and #y=-4# Explanation: #3*(4x-y)+3x+3y=3*(-4)+(-18)# #12x-3y+3x+3y=(-12)+(-18)# #15x=-30#, so #x=-2# Hence, #4*(-2)-y=-4# #-8-y=-4# #y=(-8)-(-4)=-4# Answer link Related questions What if the elimination method results in 0=0? How do you use the addition and subtraction method to solve a linear system? Can any system be solved using the addition and subtraction method? When is the addition and subtraction method easier to use? How do you solve #-x-6y=-18# and #x-6y=-6# using the addition and subtraction method? How do you solve #5x-3y=-14# and #x-3y=2# using elimination? Do you need to add or subtract the equations #5x+7y=-31# and #5x-9y=17# to solve the system? How do you solve the system of equations #3y-4x=-33# and #5x-3y=40.5#? What is the solution to the system #x+y=2# and #x-y=6#? What is the common point of #x+2y=6# and #x+y=2#? See all questions in Linear Systems with Addition or Subtraction Impact of this question 1620 views around the world You can reuse this answer Creative Commons License