How do you solve the exponential inequality #2^(x+3)<=16^(4x-2)#? Precalculus Solving Rational Inequalities Polynomial Inequalities 1 Answer Cesareo R. Feb 17, 2017 #x ge 11/15# Explanation: Knowing that #16=2^4# we have #2^(x+3) le 2^(4(4x-2))# Here #2 > 1# then if #2^alpha le 2^beta->alpha le beta# so #x+3 le 16x-8->15xge 11->x ge 11/15# Answer link Related questions What are common mistakes students make when solving polynomial inequalities? How do I solve a polynomial inequality? How do I solve the polynomial inequality #-2(m-3)<5(m+1)-12#? How do I solve the polynomial inequality #-6<=2(x-5)<7#? How do I solve the polynomial inequality #1<2x+3<11#? How do I solve the polynomial inequality #-12<-2(x+1)<=18#? How do you solve the inequality #6x^2-5x>6#? How do you solve #x^2 - 4x - 21<=0# A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)? How do you solve quadratic inequality, graph, and write in interval notation #x^2 - 8x + 15 >0#? How do you solve #-x^2 - x + 6 < 0#? See all questions in Polynomial Inequalities Impact of this question 1153 views around the world You can reuse this answer Creative Commons License