How do you solve the equation #x^2-8x+11=0# by completing the square?

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How do you solve the equation #x^2-8x+11=0# by completing the square?

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Answer 1 · 2016-12-05T18:43:17

#x=4+sqrt5# and
#x=4-sqrt5#

Explanation:

#x^2-2(x)(4)+(4)^2-(4)^2+11# add and subtract #(4)^2#
#(x-4)^2-5=0#
#(x-4)^2=5#
taking sq root both sides#sqrt((x-4)^2)=sqrt5#
#x-4=+-sqrt5#
#x=4+-sqrt5#

Therefore
#x=4+sqrt5# and
#x=4-sqrt5#

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How do you solve the equation #x^2-8x+11=0# by completing the square?

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