How do you solve the equation #x^2+6x+13=0# by completing the square?
1 Answer
Jan 8, 2017
Explanation:
The difference of squares identity can be written:
#a^2-b^2 = (a-b)(a+b)#
Use this with
#0 = x^2+6x+13#
#color(white)(0) = x^2+6x+9+4#
#color(white)(0) = (x+3)^2-(2i)^2#
#color(white)(0) = ((x+3)-2i)((x+3)+2i)#
#color(white)(0) = (x+3-2i)(x+3+2i)#
Hence:
#x = -3+-2i#
