How do you solve the equation x^2+2x-120=0 by completing the square?
1 Answer
Dec 4, 2016
Explanation:
The difference of squares identity can be written:
a^2-b^2 = (a-b)(a+b)
So we find:
0 = x^2+2x-120
color(white)(0) = x^2+2x+1-121
color(white)(0) = (x+1)^2-11^2
color(white)(0) = ((x+1)-11)((x+1)+11)
color(white)(0) = (x-10)(x+12)
Hence:
x = 10 orx = -12