How do you solve the equation x^2-2/3x-26/9=0 by completing the square?
1 Answer
Jan 8, 2017
Explanation:
Given:
x^2-2/3x-26/9 = 0
The difference of squares identity can be written:
a^2-b^2 = (a-b)(a+b)
Use this with
0 = x^2-2/3x-26/9
color(white)(0) = x^2-2/3x+1/9-3
color(white)(0) = (x-1/3)^2-(sqrt(3))^2
color(white)(0) = ((x-1/3)-sqrt(3))((x-1/3)+sqrt(3))
color(white)(0) = (x-1/3-sqrt(3))(x-1/3+sqrt(3))
Hence:
x = 1/3+-sqrt(3)
