How do you solve the equation and identify any extraneous solutions for $4 abs(4-3x )= 4x + 6$ ?

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Answer 1 · 2015-07-12T20:22:00

Verify those numbers!

$4(4−3x)=4xs+6s, s = ±1$

$16−12x=4sx+6s$

$16-6s=4sx+12x$

$(16-6s)/(4s + 12)=x$

$s = 1 \Rightarrow x = 10/16 = 5/8$

$s = -1 \Rightarrow x = 22/8 = 11/4$

How do you solve the equation and identify any extraneous solutions for 4 abs(4-3x )= 4x + 64 abs(4-3x )= 4x + 6?