How do you solve the equation #abs(2x+6)=12#?

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Answer 1 · 2018-03-18T18:48:07

#x=3 orx=-9#

Here,
#|2x+6|=12#

#=>2x+6=12 or 2x+6=-12#

Adding (-6) to the both sides of each equation,

#=>2x+cancel(6)+(cancel((-)6)=12+(-6)=12-6#

#or2x+cancel(6)+(cancel(-6))=-12+(-6)=-12-6#

#=>2x=6 or 2x=-18#

Dividing both sides of each equation by 2,we get

#(cancel(2)x)/cancel(2)=cancel(6)^3/cancel(2) or(cancel(2)x)/cancel(2)=-cancel(18)^9/cancel(2)#

#x=3 orx=-9#