How do you solve the equation $4x^2-28x+49=5$ by completing the square?

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Answer 1 · 2018-06-01T08:53:04

$4(x^2-7x + (7/2)^2 )=5-49+4(7/2)^2$

$4(x-7/2)^2=5$

$(2x - 7)^2 = 5$

$x = 1/2 ( 7 pm sqrt{5} )$

How do you solve the equation 4x^2-28x+49=54x^2-28x+49=5 by completing the square?