How do you solve the equation 3sin2theta - 2cos2theta = 23sin2θ−2cos2θ=2 for 0 <= theta <= 2pi0≤θ≤2π, using the substitution t=tanthetat=tanθ?
1 Answer
May 20, 2018
Explanation:
Recall that, if,
and,
Hence, sub.ing in the given eqn. :