How do you solve $(t-3)/(t+6)>0$ using a sign chart?

Question

1609 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-25T12:47:06

Solution: $t < -6 and t > 3$ In interval notation:
$t| (-oo,-6)uu (3,oo)$

$(t-3)/(t+6)>0 ; t != -6$ as the function is undefined at $t=-6$

Critical points are $t=3 and t = -6$

Sign chart:

When $t <-6$ sign of $f(t)$ is $(-)/(-)=(+) ; >0$

When $-6 < t<3$ sign of $f(t)$ is $(-)/(+)=(-) ; <0$

When $t > 3$ sign of $f(t)$ is $(+)/(+)=(+) ; >0$

Solution: $t < -6 and t > 3$ . In interval notation:

$t| (-oo,-6)uu (3,oo)$

How do you solve (t-3)/(t+6)>0(t-3)/(t+6)>0 using a sign chart?