How do you solve $t^2<3(2t-3)$ using a sign chart?

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Answer 1 · 2017-01-22T11:38:20

The answer is $S=O/$

Let's rewrite the inequality

$t^2<3(2t-3)$

$t^2-3(2t-3)<0$

$t^2-6t+9<0$

Let's factorise

$(t-3)(t-3)<0$

$(t-3)^2<0$

This is impossible since $(t-3)^2>=0, AA x in RR$

How do you solve t^2<3(2t-3)t^2<3(2t-3) using a sign chart?