How do you solve $\frac{sin B}{3} = \frac{sin 55}{7}$ $sinB/3=sin55/7$ ?

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Answer 1 · 2016-11-09T17:57:40

20.5524...

First you work out $\frac{sin 55}{7}$ $sin55/7$ by using your calculator

=0.11702... (keep that number in your calculator)

times by 3 to get sinB

=0.3510651....=sinB (keep in calculator)

as it is sinB you need to ${sin}^{- 1}$ $sin^-1$ the number

$sin^-1(0.3510651...)= 20.5524...$

How do you solve sinB/3=sin55/7sinB3=sin557sinB/3=sin55/7?