How do you solve $SinA/14=sin104^o/25$ ?

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Answer 1 · 2016-12-18T06:41:54

$A=32.9^o$

In $sinA/14=sin104^o/25$

as $sin104^o=0.9703$ - using tables or scientific calculator, however note that $sin104^o=sin(180^o-76^o)=sin76^o$

we have $sinA/14=0.9703/25$

and $sinA=14xx0.9703/25=0.5437$

and again using tables or scientific calculator

$A=32.9^o$

How do you solve SinA/14=sin104^o/25SinA/14=sin104^o/25?