How do you solve #sin(theta)= 0.4# over the interval 0 to 2pi?

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How do you solve #sin(theta)= 0.4# over the interval 0 to 2pi?

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Answer 1 · 2016-10-31T13:11:40

#23^@58 and 156^#42 for (0, 360)#

Explanation:

Use calculator:
sin x = 0.4 --> arc #x = 23^@58#
Trig unit circle gives another arc x that has the same sin value:
#x = 180 - 23.58 = 156^@42#
Answers for (0, 360)
#23^@58, 156^@42#

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How do you solve #sin(theta)= 0.4# over the interval 0 to 2pi?

1 Answer

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