How do you solve #(m+3)/4=(m-5)/7#?

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Answer 1 · 2016-08-02T19:26:17

#m=-41/3#

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#(m+3)/4=(m-5)/7 larr" Cross multiply giving:"#

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#7(m+3)=4(m-5) larr" Multiply out the brackets giving:"#

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#7m+21=4m-20 larr" Collecting like terms giving:"#

#7m-4m=-21-20#

#3m=-41 larr" divide both sides by 3 giving:"#

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#m=-41/3#