How do you solve $(m+3)/4=(m-5)/7$ ?

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Answer 1 · 2016-08-02T19:26:17

$m=-41/3$

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$(m+3)/4=(m-5)/7 larr" Cross multiply giving:"$

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$7(m+3)=4(m-5) larr" Multiply out the brackets giving:"$

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$7m+21=4m-20 larr" Collecting like terms giving:"$

$7m-4m=-21-20$

$3m=-41 larr" divide both sides by 3 giving:"$

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$m=-41/3$

How do you solve (m+3)/4=(m-5)/7(m+3)/4=(m-5)/7?