How do you solve $\frac{m + 1}{4} = \frac{3 m + 6}{7}$ $(m+1)/4=(3m+6)/7$ ?

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How do you solve $\frac{m + 1}{4} = \frac{3 m + 6}{7}$ $(m+1)/4=(3m+6)/7$ ?

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Answer 1 · 2016-08-09T10:04:07

$m = - \frac{17}{5}$ $m=-17/5$

Explanation:

$\frac{m + 1}{4} = \frac{3 m + 6}{7}$ $(m+1)/4=(3m+6)/7$
or
$7 m + 7 = 12 m + 24$ $7m+7=12m+24$
or
$12 m - 7 m = 7 - 24$ $12m-7m=7-24$
or
$5 m = - 17$ $5m=-17$
or
$m = - \frac{17}{5}$ $m=-17/5$

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How do you solve $\frac{m + 1}{4} = \frac{3 m + 6}{7}$ $(m+1)/4=(3m+6)/7$ ?

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How do you solve $\frac{m + 1}{4} = \frac{3 m + 6}{7}$ $(m+1)/4=(3m+6)/7$ ?