How do you solve #logx+log8=2#?

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Answer 1 · 2018-06-22T10:08:17

#x=25/2#

#log x+log 8=2#

#log8x=2#

#log_10 8x=2#

#8x=10^2#

#8x=100#

#x=100/8#

#x=25/2#

Recall that if it just says #log#, it means #log_10#
and the log law: #log a+ log b=logab#