How do you solve #log7 + log (n - 2) = log 6n#?

1 Answer
Steve M
Apr 28, 2018

# n= 14 #

Explanation:

We have:

# log7 + log (n - 2) = log 6n #

Using the log properties:

# log ab = log a + logb #
# log a = log b iff a=b #

So that:

# log 7(n - 2) = log 6n #

# :. 7(n - 2) = 6n #

# :. 7n-14 = 6n #
# :. 7n-6n = 14 #
# :. n= 14 #

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